A) \[CdS,\,\,B{{i}_{2}}{{S}_{3}}\]
B) \[B{{i}_{2}}{{S}_{3}},\,\,PbS\]
C) \[PbS,\,\,HgS\]
D) \[CdS,\,\,A{{g}_{2}}{{S}_{3}}\]
Correct Answer: D
Solution :
The sulphides of group \[IIA\] are\[PbS,\]\[B{{i}_{2}}{{S}_{3}},\]\[CdS,\]\[HgS\]. The sulphides of group \[IIB\] are\[A{{s}_{2}}{{S}_{5}},\,\,S{{b}_{2}}{{S}_{5}},\,\,Sn{{S}_{2}},\,\,A{{g}_{2}}{{S}_{3}}\]. In choice (a), (b) and (c) both the sulphides belong to group\[IIA\]. So they cannot be separated by yellow ammonium sulphide. In choice (d) \[CdS\] is of group \[IIA\] and\[A{{g}_{2}}{{S}_{3}}\] belongs to group IIB. So they can be separated by yellow ammonium sulphide.
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