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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    A metal coin is at the bottom of a beaker filled with a liquid of refractive index 4/3 to height of 6 cm. To an observer looking from above the surface of the liquid, coin will appear at a depth of:

    A)  7.5 cm                                 

    B)  6.75 cm

    C)  4.5 cm                 

    D)         1.5 cm

    Correct Answer: D

    Solution :

    Here: Actual depth of liquid h= 6 cm Refractive index of the liquid \[=\frac{4}{3}\] Using the relation      \[\mu =\frac{actual\,depth\,(h)}{apparent\,depth\,(x)}\] or     \[x=h\times \frac{3}{4}=6\times \frac{3}{4}=4.5\,cm\] Hence, the coin will appear at a depth of                       \[=6-4.5=1.5\,cm\]


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