RAJASTHAN PMT Rajasthan - PMT Solved Paper-2005

  • question_answer
    A car is moving at a speed of 72 km/hr. The diameter of its wheels is 0.5 m. If the wheels are stopped in 20 rotations applying brakes. Then angular retardation provided by the brake is:

    A)  \[-45.\,5\,rad/{{s}^{2}}\]                            

    B)  \[-33.\,5\,rad/{{s}^{2}}\]

    C)  \[-29.\,5\,rad/{{s}^{2}}\]

    D)         \[-25.\,5\,rad/{{s}^{2}}\]

    Correct Answer: D

    Solution :

    Here: Speed of car\[=72km/hr\] \[\frac{72\times 5}{18}=20\,cm/s\] Diameter of each wheel \[\frac{0.5}{2}\,m\] Number of rotation = 20 The relation for angular speed is\[\omega =\frac{\upsilon }{r}\,=\frac{20}{0.25}=80\,rad/\sec \]Angular is placement \[Q=2\pi \times 20=40\pi \,rad\] The relation for angular retardation is given by \[{{\omega }^{2}}={{\omega }^{2}}+2aQ\] \[0={{(80)}^{2}}+2a(40\pi )\] or            \[a=\frac{{{(80)}^{2}}}{80\pi }=-25.5\,rad/{{s}^{2}}\]


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