A) \[4.157\times {{10}^{23}}\]
B) \[3.343\times {{10}^{23}}\]
C) \[6.023\times {{10}^{23}}\]
D) \[8.527\times {{10}^{23}}\]
Correct Answer: C
Solution :
Number of atoms in \[1\text{ }mole\]\[(17\,gm)\] \[N{{H}_{3}}\] \[=4\times 6.023\times {{10}^{23}}\] \[\therefore \] Number of atoms in \[~4.25gm\] \[N{{H}_{3}}\] \[=\frac{4\times 6.023\times {{10}^{23}}}{17}\times 4.25\] \[=6.023\times {{10}^{23}}\]
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