A) \[ClC{{H}_{2}}C{{H}_{2}}Cl\]
B) \[C{{l}_{2}}C=C{{H}_{2}}\]
C) \[C{{l}_{2}}C=CC{{l}_{2}}\]
D) \[ClCH=CHCl\]
Correct Answer: D
Solution :
\[ClCH=CHCl\] shows cis-trans geometry isomerism.
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