A) \[{{K}_{a}}.C\]
B) \[C/{{K}_{a}}\]
C) \[\sqrt{{{K}_{a}}.C}\]
D) \[\sqrt{{{K}_{a}}/C}\]
Correct Answer: D
Solution :
\[HA{{H}^{+}}+{{A}^{-}}\] \[{{K}_{a}}=\frac{{{C}^{2}}{{x}^{2}}}{C(a-x)}\] \[\frac{{{C}^{2}}{{x}^{2}}}{C}\](For weak acid\[1-x=1\]) \[C.\,{{K}_{a}}={{C}^{2}}{{x}^{2}}=Cx=\sqrt{{{K}_{a}}.C}\] \[\therefore \] \[[{{H}^{+}}]=Cx=\sqrt{{{K}_{a}}.C}\]You need to login to perform this action.
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