RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    When plate voltage in diode valve is increased from 100 volt to 150 volt. Then plate current increases from 7.5 mA to 12 mA, then dynamic plate resistance will be:

    A)  10 \[k\Omega \]             

    B)         11\[k\Omega \]

    C)  15\[k\Omega \]              

    D)         11.1\[k\Omega \]

    Correct Answer: D

    Solution :

    Plate resistance \[\Delta {{r}_{p}}=\frac{\Delta {{V}_{{{P}_{2}}}}-\Delta {{V}_{{{P}_{1}}}}}{{{\Delta }^{i}}_{{{P}_{1}}}}\] \[=\frac{150-100}{(12-7.5)\times {{10}^{-3}}}\] \[=\frac{50\hat{\ }{{10}^{3}}}{4.5}\] \[=11.1\,k\Omega \]


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