RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A ball is released from certain height which looses 50% of its kinetic energy on striking the ground it will attain a height again:

    A) \[\frac{1}{4}\]th of initial height                 

    B) \[\frac{1}{2}\]th of initial height

    C)  \[\frac{3}{4}\]th of initial height

    D)  none of these

    Correct Answer: B

    Solution :

     Ratio of heights \[\frac{{{h}_{1}}}{{{h}_{2}}}=\frac{100}{100-50}=2\] \[{{h}_{2}}=\frac{{{h}_{1}}}{2}=\frac{1}{2}\]of the initial height.


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