A) 4 : 1
B) 1 : 4
C) \[\sqrt{2}:1\]
D) 1 : 2
Correct Answer: D
Solution :
Linear momentum \[p=\sqrt{2mE}\]energy is same- \[\therefore \] \[\frac{{{p}_{1}}}{{{P}_{2}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}=\sqrt{\frac{10}{40}}\] = 1 : 2
You need to login to perform this action.
You will be redirected in
3 sec
