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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    In nth orbit of hydrogen atom energy \[e=\frac{13.6}{{{n}^{2}}}eV,\]then energy required to displace electrons from\[n=1\,\text{to}\,n=\,2\]is:

    A)  -10.2 eV             

    B)         3.4 eV

    C)  -13.6 eV             

    D)         1.51 eV

    Correct Answer: A

    Solution :

    Energy required to displace electron from \[n=1\,to\,n=2\] \[E=-13.6\left\{ \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right\}\] \[=-13.6\times \frac{3}{4}=-10.2\,eV\]


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