A) \[\frac{{{\upsilon }_{0}}}{2}\]
B) \[{{\upsilon }_{0}}\]
C) \[{{\upsilon }_{0}}\sqrt{\frac{3}{2}}\]
D) \[{{\upsilon }_{0}}\sqrt{\frac{3}{2}}\]
Correct Answer: D
Solution :
\[{{\upsilon }_{\max }}=a\omega \] \[{{\upsilon }_{0}}=a\omega \] Velocity \[{{\upsilon }_{1}}=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\] \[=\omega \sqrt{{{a}^{2}}-\frac{{{a}^{2}}}{4}}=\frac{\sqrt{3}}{2}a\omega =\frac{\sqrt{3}}{2}{{\upsilon }_{0}}\]
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