A) \[C{{l}_{2}}\]
B) \[PC{{l}_{5}}\]
C) \[SOC{{l}_{2}}\]
D) \[ZnC{{l}_{2}}+HCl\]
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}OH+SOC{{l}_{2}}\to {{C}_{2}}{{H}_{5}}Cl+S{{O}_{2}}+HCl\] \[{{C}_{2}}{{H}_{5}}OH+PC{{l}_{5}}\to {{C}_{2}}{{H}_{5}}Cl+POC{{l}_{3}}+HCl\] \[{{C}_{2}}{{H}_{5}}OH+HCl\xrightarrow{ZnC{{l}_{2}}}{{C}_{2}}{{H}_{5}}Cl+{{H}_{2}}O\]
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