RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    The reactance of an inductor at\[{{10}^{4}}Hz\]. is \[{{10}^{4}}\Omega ,\]then its reactance at \[2\times {{10}^{4}}Hz\]is:

    A) \[{{10}^{4}}\Omega \]                                  

    B)        \[2\times {{10}^{4}}\Omega \]                                  

    C)        \[3\times {{10}^{4}}\Omega \]                  

    D)        \[4\times {{10}^{4}}\Omega \]

    Correct Answer: B

    Solution :

    Reactance of inductance is directly proportional to angular frequency \[{{X}_{L}}\propto \omega \] \[\frac{{{X}_{{{L}_{1}}}}}{{{X}_{{{L}_{2}}}}}=\frac{{{\omega }_{1}}}{{{\omega }_{2}}}\] \[\frac{{{10}^{4}}}{{{X}_{{{L}_{2}}}}}=\frac{{{10}^{4}}}{2\times {{10}^{4}}}\] \[{{X}_{{{L}_{2}}}}=2\times {{10}^{4}}\Omega \]


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