RAJASTHAN PMT Rajasthan - PMT Solved Paper-1995

  • question_answer
    Length of a sonometer wire is \[l\]and its tension is T. If tension is made half, then its second harmonics is equal to first harmonics. Then the length of wire will be:

    A) \[\frac{l}{\sqrt{2}}\] 

    B)                         \[\frac{l}{2}\]                                   

    C)         \[l\]                                      

    D)         \[\frac{3l}{2}\]

    Correct Answer: A

    Solution :

                   Frequency of sonometer wire \[{{n}_{1}}=\sqrt{\frac{T}{2l}},\]     \[{{n}_{2}}=\sqrt{\frac{T/2}{2{{l}_{1}}}}\] Putting \[{{n}_{1}}={{n}_{2}},\,l=\frac{l}{\sqrt{2}}\]         


You need to login to perform this action.
You will be redirected in 3 sec spinner