A) \[MC{{l}_{2}}\]is more volatile than \[MC{{l}_{4}}\]
B) \[MC{{l}_{2}}\]is more soluble in anhydrous ethanol than\[MC{{l}_{4}}\]
C) \[MC{{l}_{2}}\]is more ionic than\[MC{{l}_{4}}\]
D) \[MC{{l}_{2}}\]is more easily hydrolysed than\[MC{{l}_{4}}\]
Correct Answer: C
Solution :
\[MC{{l}_{2}};\] oxidation state of \[M=+2\] \[MC{{l}_{4}};\]oxidation state of \[M=+4\] Higher the oxidation state, smaller the size. Greater the polarising power, greater is the covalent character. Hence,\[MC{{l}_{4}}\]is more covalent and\[MC{{l}_{2}}\]is more ionic.
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