A) \[C{{H}_{3}}COC{{H}_{2}}COO{{C}_{2}}{{H}_{5}}\]
B) \[PhC{{H}_{2}}COC{{H}_{3}}\]
C) \[M{{e}_{3}}C.COC{{H}_{3}}\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: A
Solution :
lodoform test is given by those compounds which contain\[C{{H}_{3}}CO-\]group. Ethyl acetoacetate\[(C{{H}_{3}}COC{{H}_{2}}COO{{C}_{2}}{{H}_{5}})\]contains\[C{{H}_{3}}CO-\]group but it is attached to more reactive\[-C{{H}_{2}}\]group (methylene group). Therefore, on reaction with\[{{I}_{2}}\]and\[O{{H}^{-}},\]the iodination of\[-C{{H}_{2}}\]group is rapidi than the methyl group of\[C{{H}_{3}}CO-\]. Due to this reason ethyl acetoacetate does not give iodoform test.
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