A) 1 : 2
B) 1 : 4
C) 2 : 1
D) 4 : 1
Correct Answer: A
Solution :
The excess pressure inside the bubble \[p=\frac{4T}{r}\] Then, \[{{p}_{1}}=\frac{4T}{{{r}_{1}}}\] ...(i) \[{{p}_{2}}=\frac{4T}{{{r}_{2}}}\] ?.(ii) From Eqs. (i) and (ii) \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{\frac{4T}{{{r}_{1}}}}{\frac{4T}{{{r}_{2}}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{1}{2}\]
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