A) 700 K
B) 600 K
C) 400 K
D) 500 K
Correct Answer: C
Solution :
\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\Rightarrow 0.4=1-\frac{500}{{{T}_{1}}}\] \[\Rightarrow \] \[\frac{500}{{{T}_{1}}}=0.6\] ??..(i) Similarly, \[\frac{1}{2}=1-\frac{{{T}_{2}}'}{{{T}_{1}}}\Rightarrow \frac{{{T}_{2}}'}{{{T}_{1}}}=\frac{1}{2}\] ...(ii) Dividing Eq. (i) by Eq. (ii), we get\[{{T}_{2}}'=400\,K\]
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