A) \[\frac{L}{6}\]
B) \[\frac{L}{3}\]
C) \[\frac{L}{4}\]
D) \[\frac{L}{2}\]
Correct Answer: A
Solution :
\[{{I}_{CM}}=\frac{M{{L}^{2}}}{12}\] where L = length of rod. According to theorem of parallel axis, moment of inertia about axis MM' \[\frac{M{{L}^{2}}}{9}=\frac{M{{L}^{2}}}{12}+M{{r}^{2}}\] \[r=\frac{L}{6}\]You need to login to perform this action.
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