RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    The second Bohr's radius of hydrogen atom is

    A)  \[0.529\overset{o}{\mathop{\text{A}}}\,\]         

    B)  3.125\[\overset{o}{\mathop{\text{A}}}\,\]

    C)  2.1165\[\overset{o}{\mathop{\text{A}}}\,\]        

    D)  4.2\[\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

     \[{{r}_{n}}=\frac{0.529{{n}^{2}}}{Z}\overset{o}{\mathop{\text{A}}}\,\] \[=\frac{0.529{{(2)}^{2}}}{1}\] \[=0.529\times 4=2.116\overset{o}{\mathop{\text{A}}}\,\]


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