A) \[\frac{1}{2}kT\]
B) \[\frac{3}{2}kT\]
C) \[\frac{1}{2}RT\]
D) \[\frac{3}{2}RT\]
Correct Answer: B
Solution :
Average kinetic energy of one molecule of ideal gas \[E=\frac{3}{2}KT\]
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