A) \[60{}^\circ \]
B) \[45{}^\circ \]
C) \[30{}^\circ \]
D) \[75{}^\circ \]
Correct Answer: B
Solution :
According to question,\[R=4H\] \[\Rightarrow \] \[\frac{{{u}^{2}}\sin 2\theta }{g}=4.\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] Or \[\frac{2{{u}^{2}}\sin \cos \theta }{g}=\frac{2{{u}^{2}}{{\sin }^{2}}\theta }{g}\] Or \[\tan \theta =1\] Or \[\theta =45{}^\circ \]
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