A) \[30N\]
B) \[26N\]
C) \[20N\]
D) \[6N\]
Correct Answer: C
Solution :
Tension in the string when it makes angle \[\theta \] with the vertical, \[T=\frac{m{{v}^{2}}}{r}+mg\cos \theta \] When the string is horizontal,\[\theta ={{90}^{o}}\] Here,\[m=0.6\,\,kg,\,\,r=0.75\,\,m,\,\,v=5m/s\] Hence, \[T=\frac{m{{v}^{2}}}{r}+mg\times 0=\frac{m{{v}^{2}}}{r}\] \[\therefore \] \[T=\frac{0.6\times {{(5)}^{2}}}{0.75}=20\,\,N\]You need to login to perform this action.
You will be redirected in
3 sec