A) \[10{}^\circ \]
B) \[24{}^\circ \]
C) \[50{}^\circ \]
D) \[\frac{1}{6}{}^\circ \]
Correct Answer: B
Solution :
Magnification,\[m=\frac{{{f}_{0}}}{{{f}_{e}}}\] Also\[\text{m=}\frac{\text{Angle}\,\,\text{subtanded}\,\,\text{by}\,\,\text{the}\,\,\text{image}}{\text{Angle}\,\,\text{subtended}\,\,\text{by}\,\,\text{the}\,\,\text{object}}\] \[\therefore \] \[\frac{{{f}_{o}}}{{{f}_{e}}}=\frac{\alpha }{\beta }\,\,\,\Rightarrow \,\,\,\alpha =\frac{{{f}_{o}}\times \beta }{{{f}_{e}}}\] \[=\frac{60\times 2}{5}\] \[={{24}^{o}}\]
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