A) \[0.80M\]
B) \[1.0M\]
C) \[0.73M\]
D) \[0.50M\]
Correct Answer: C
Solution :
Moles of \[2.5L\] of \[1M\,\,NaOH=2.5\times 1=2.5\] Moles of \[3.0L\] of \[0.5M\,\,NaOH=3.0\times 0.5=1.5\] Total moles of \[NaOH\] in solution\[=2.5+1.5=4.0\] (Total volume of solution\[=2.5+3.0=5.5L\]) Thus \[{{M}_{1}}\times {{V}_{1}}={{M}_{2}}\times {{V}_{2}}\] \[4.0={{M}_{2}}\times 5.5\] \[\therefore \]molarity of resultant solution\[={{M}_{2}}=\frac{4.0}{5.5}M\]
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