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Punjab Medical Punjab - MET Solved Paper-2001

  • question_answer
    From a point charge, there is a fix point\[A\]. At\[A\], there is an electric fit of \[500\,\,V/m\] and potential difference\[3000\,\,V\]. Distance between point char and point \[A\] is

    A) \[24\,\,m\]                        

    B) \[16\,\,m\]

    C) \[12\,\,m\]                        

    D) \[6\,\,m\]

    Correct Answer: D

    Solution :

    Here: Electric field\[E=500\,\,V/m\] Potential difference\[V=3000\,\,V\] Using the relation, Electric field\[E=\frac{V}{d}\] or            \[d=\frac{V}{E}=\frac{3000}{500}=6\,\,m\]


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