A) \[400\,\,m/s\]
B) \[250\,\,m/s\]
C) \[100\,\,m/s\]
D) \[200\,\,m/s\]
Correct Answer: D
Solution :
Here: Equation of standing wave \[y=0.3\sin (314t-1.57x)\] \[y=0.3\sin 2\pi \left( \frac{314t}{2\pi }-\frac{1.57x}{2\pi } \right)\] or \[y=\frac{0.30}{100}\sin 2\pi \left( 50t-\frac{v}{4} \right)\] ... (1) The standard equation of standing wave is \[y=a\sin 2\pi \left( \frac{t}{T}-\frac{x}{\lambda } \right)\] ... (2) Comparing the given equation (1) with the standard equation (2) we obtain or \[\frac{1}{T}=50\] and \[\lambda =4\] Hence, the velocity of wave is given by \[v=n\,\,\lambda =\frac{1}{T}\times \lambda =50\times 4=200\,\,m/s\]
You need to login to perform this action.
You will be redirected in
3 sec
