NEET NEET SOLVED PAPER 2018

  • question_answer
    A sample of 0.1 g of water at \[\text{100 }\!\!{}^\circ\!\!\text{ C}\] and normal pressure \[\text{(1}\text{.013 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{5}}}\text{N}{{\text{m}}^{\text{--2}}}\text{)}\] requires 54 cal of heat energy to convert to steam at\[\text{100 }\!\!{}^\circ\!\!\text{ C}\]. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample, is [NEET - 2018]

    A)  42.2 J            

    B)  208.7 J

    C)  104.3 J                      

    D)  84.5 J

    Correct Answer: B

    Solution :

    \[\Delta \text{Q=}\Delta \text{U+}\Delta \text{W}\] \[\Rightarrow 54\times 4.18=\Delta U+1.013\times {{10}^{5}}(167.1\times {{10}^{-6}}-0)\] \[\Rightarrow \Delta U=208.7\,\,\text{J}\]


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