question_answer

Predict the correct intermediate and product in the following reaction                                   \[{{H}_{3}}C-C\equiv CH\xrightarrow[HgS{{O}_{4}}]{{{H}_{2}}O,{{H}_{2}}S{{O}_{4}}}\underset{\text{(A)}}{\mathop{\text{intermediate}}}\,\xrightarrow{{}}\underset{\text{(B)}}{\mathop{\text{product}}}\,\]

A) \[A:{{H}_{3}}C-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]   \[B:{{H}_{3}}C-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\]

B)  \[A:{{H}_{3}}C-\underset{S{{O}_{4}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]    \[B:{{H}_{3}}C-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,=C{{H}_{3}}\]

C)  \[A:{{H}_{3}}C-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]  \[B:{{H}_{3}}C-\underset{S{{O}_{4}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]

D)  \[A:{{H}_{3}}C-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\]    \[B:{{H}_{3}}C-C\equiv CH\]

Correct Answer: A

Solution :