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NEET NEET SOLVED PAPER 2017

  • question_answer
    The equilibrium constants of the following are.                                                                                  \[{{N}_{2}}+3{{H}_{2}}\rightleftharpoons 2N{{H}_{3}}\,{{K}_{4}}\] \[{{N}_{2}}+{{O}_{2}}\rightleftharpoons 2NO\,{{K}_{2}}\] \[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}{{H}_{2}}O\,{{K}_{3}}\] The equilibrium constant (K) of the reaction \[2N{{H}_{3}}+\frac{5}{2}{{O}_{2}}\xrightarrow{k}2NO+3{{H}_{2}}O,\]will be

    A) \[K_{2}^{3}{{K}_{3}}/{{K}_{1}}\]

    B) \[{{K}_{1}}K_{3}^{3}/{{K}_{2}}\]

    C) \[{{K}_{2}}K_{3}^{3}/{{K}_{1}}\]                               

    D) \[{{K}_{2}}{{K}_{3}}/{{K}_{1}}\]

    Correct Answer: C

    Solution :

                     (i) \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}};{{K}_{1}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]{{[{{H}_{2}}]}^{3}}}\]                 (ii) \[{{N}_{2}}+{{O}_{2}}2NO;{{K}_{2}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}\] (iii) \[{{H}_{2}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}{{H}_{2}}O;{{K}_{3}}=\frac{[{{H}_{2}}O]}{[{{H}_{2}}]{{[{{O}_{2}}]}^{1/2}}}\] \[(II+3\times III-II)\]will give \[2N{{H}_{3}}+\frac{5}{2}{{O}_{2}}2NO+3{{H}_{2}}O;\] \[\therefore \]  \[K={{K}_{2}}\times K_{3}^{3}/{{K}_{1}}\]


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