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NEET NEET SOLVED PAPER 2017

  • question_answer
    The\[x\]and y coordinates of the particle at any time are \[x=5t-2{{t}^{2}}\]and \[y=10t\]respectively, where\[x\] and y are in meters and t in seconds. The acceleration of the particle at t = 2 s is                                

    A) \[-8\,m/{{s}^{2}}\]                         

    B)   0

    C)   \[5\,m/{{s}^{2}}\]                         

    D)  \[-4\,m/{{s}^{2}}\]

    Correct Answer: D

    Solution :

                     \[x=5t-2{{t}^{2}}\]                          \[y=10t\] \[\frac{dx}{dt}=5-4t\]                    \[\frac{dy}{dt}=10\] \[{{v}_{x}}=5-4t\]                             \[{{v}_{y}}=10\] \[\frac{dv}{dt}x=-4\]                      \[\frac{dv}{dt}y=10\] \[{{a}_{x}}=-4\]                 \[{{a}_{y}}=0\] Acceleration of particle at t = 2 s is\[~=4\text{ }m/{{s}^{2}}\]


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