A) \[\frac{d\ell nG}{d{{T}^{2}}}=\frac{\Delta {{ }_{v}}}{R{{T}^{2}}}\]
B) \[\frac{d\ell nP}{dT}=\frac{-\Delta {{ }_{v}}}{RT}\]
C) \[\frac{d\ell nP}{d{{T}^{2}}}=\frac{-\Delta {{ }_{v}}}{{{T}^{2}}}\]
D) \[\frac{d\ell nP}{dT}=\frac{\Delta {{ }_{v}}}{R{{T}^{2}}}\]
Correct Answer: D
Solution :
Clausius - Clapeyron's equation\[\frac{d\,\ln P}{dT}=\frac{\Delta {{H}_{v}}}{R{{T}^{2}}}\]
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