A) 5 : 1
B) 5 : 4
C) 3 : 4
D) 3 : 2
Correct Answer: D
Solution :
\[\frac{{{E}_{1}}+{{E}_{2}}}{{{E}_{1}}-{{E}_{2}}}=\frac{50}{10}\] \[\Rightarrow \] \[\frac{2{{E}_{1}}}{2{{E}_{2}}}=\frac{50+10}{50-10}\Rightarrow \frac{{{E}_{1}}}{{{E}_{2}}}=\frac{3}{2}\]You need to login to perform this action.
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