2. Solved Papers
  3. NEET

NEET NEET SOLVED PAPER 2016 Phase-II

  • question_answer
    In the given figure,\[a=15m/{{s}^{2}}\]represents the total acceleration of a particle moving in the clockwise direction in a circle of radius \[R=2.5\]m at a given instant of time. The speed of the particle is

    A)  4.5 m/s            

    B)  5.0 m/s

    C)  5.7 m/s            

    D)  6.2 m/s

    Correct Answer: C

    Solution :

    \[a\cos \,{{30}^{{}^\circ }}=\frac{{{V}^{2}}}{r}\] \[\Rightarrow 15\frac{\sqrt{3}}{2}=\frac{{{V}^{2}}}{2.5}\] \[\Rightarrow V=5.7\,m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner