A)
B)
C)
D)
Correct Answer: B
Solution :
\[gin=\frac{GMr}{{{R}^{3}}}\Rightarrow \,gin\,\alpha \,r\] \[g\,out=\frac{GM}{{{r}^{2}}}\Rightarrow g\,out\,\alpha \,\frac{1}{{{r}^{2}}}\]You need to login to perform this action.
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