A) \[0\,A\]
B) \[{{10}^{-2}}A\]
C) \[{{10}^{-1}}A\]
D) \[{{10}^{-3}}A\]
Correct Answer: B
Solution :
Since diode is in forward bias\[i=\frac{\Delta V}{R}=\frac{4-(-6)}{1\times {{10}^{3}}}=\frac{10}{{{10}^{3}}}={{10}^{-2}}A\]You need to login to perform this action.
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