A) \[O_{2}^{-}>{{O}_{2}}>O_{2}^{+}\]
B) \[O_{2}^{-}<{{O}_{2}}<O_{2}^{+}\]
C) \[O_{2}^{-}>{{O}_{2}}<O_{2}^{+}\]
D) \[O_{2}^{-}<{{O}_{2}}>O_{2}^{+}\]
Correct Answer: B
Solution :
Bond order of \[O_{2}^{-}\] \[O_{2}^{-}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}}\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\sigma 2p_{z}^{2}(\pi 2p_{x}^{2}=\pi 2p_{y}^{2})\]\[({{\pi }^{*}}2p_{x}^{2}={{\pi }^{*}}2p_{y}^{1})\] Bond order \[=\begin{array}{*{35}{l}} \text{number of electrons in BMO} \\ \begin{align} & \text{ - number of elections ABMO} \\ & \text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ }\!\!\_\!\!\text{ } \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2 \\ \end{align} \\ \end{array}\] \[=\frac{10-7}{2}=\frac{3}{2}=1.5\] \[O_{2}^{+}=\sigma 1{{s}^{2}},\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\sigma 2p_{z}^{2}\] \[(\pi 2p_{x}^{2}=\pi 2p_{y}^{2})({{\pi }^{*}}2p_{x}^{1}={{\pi }^{*}}2p_{y}^{0})\] \[BO=\frac{10-5}{2}=\frac{5}{2}=2.5\] \[{{O}_{2}}=\sigma 1{{s}^{2}}\overset{*}{\mathop{\sigma }}\,1{{s}^{2}},\sigma 2{{s}^{2}},\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\sigma 2p_{z}^{2}\,\,\,\,(\pi 2p_{x}^{2}=\pi 2p_{y}^{2})\] \[(\overset{*}{\mathop{\pi }}\,2p_{x}^{1}=\overset{*}{\mathop{\pi }}\,2p_{y}^{1})\] \[BO=\frac{10-6}{2}=\frac{4}{2}=2\] So, the correct sequence is \[O_{2}^{-}<{{O}_{2}}<O_{2}^{+}\]
You need to login to perform this action.
You will be redirected in
3 sec
