A) \[M{{n}^{4+}}\]and \[{{O}_{2}}\]
B) \[M{{n}^{2+}}\] and \[{{O}_{2}}\]
C) \[M{{n}^{2+}}\]and \[{{O}_{3}}\]
D) \[M{{n}^{4+}}\]and \[Mn{{O}_{2}}\]
Correct Answer: B
Solution :
The reaction of aqueous \[KMn{{O}_{4}}\] with \[{{H}_{2}}{{O}_{2}}\] in acidic medium is \[3{{H}_{2}}S{{O}_{4}}+2KMn{{O}_{4}}+5{{H}_{2}}{{O}_{2}}\to \]\[5{{O}_{2}}+2MnS{{O}_{4}}+8{{H}_{2}}O+{{K}_{2}}S{{O}_{4}}\] In the above reaction, \[KMn{{O}_{4}}\] oxidises \[{{H}_{2}}{{O}_{2}}\] to \[{{O}_{2}}\] and itself \[[MnO_{4}^{-}]\] gets reduced to \[M{{n}^{2+}}\] ion as \[MnS{{O}_{4}}\]. Hence, aqueous solution of \[KMn{{O}_{4}}\] with \[{{H}_{2}}{{O}_{2}}\] yields \[M{{n}^{2+}}\] and \[{{O}_{2}}\] in acidic conditions.
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