A) \[{{H}^{+}}\]
B) \[L{{i}^{+}}\]
C) \[N{{a}^{+}}\]
D) \[M{{g}^{2+}}\]
Correct Answer: B
Solution :
Isoelectronic species contain same number of electrons. \[B{{e}^{2+}}\]contains 2 electrons. Among the given options, only \[L{{i}^{2+}}\] contains 2 electrons and therefore, it is isoelectronic with\[B{{e}^{2+}}\]. \[{{H}^{+}}\to \]no electron; \[N{{a}^{+}}\to 10{{e}^{-}}\] \[L{{i}^{+}}\to 2{{e}^{-}};M{{g}^{2+}}\to 10{{e}^{-}}\] Hence, \[B{{e}^{2+}}\] is isoelectronic with\[L{{i}^{+}}\].
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