A) \[FeC{{l}_{3}},SnC{{l}_{2}}\]
B) \[HgC{{l}_{2}},SnC{{l}_{2}}\]
C) \[FeC{{l}_{2}},SnC{{l}_{2}}\]
D) \[FeC{{l}_{3}},Kl\]
Correct Answer: C
Solution :
The compounds with lower oxidation number and which cannot reduced by one another can exist together. Thus, \[FeC{{l}_{2}}\] and \[SnC{{l}_{2}}\] can exist together as \[F{{e}^{2+}}\] cannot be reduced by \[S{{n}^{2+}}.\]
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