A) 24 Ns
B) 20 Ns
C) 12Ns
D) 6Ns
Correct Answer: C
Solution :
The area under F-t graph gives change in momentum. For 0 to \[2\,s,\Delta {{p}_{1}}=\frac{1}{2}\times 2\times 6=6kg-m/s\] For 2 to 4 s, \[\Delta {{p}_{2}}=2\times (-3)=-6\,kg-m/s\] For 4 to 8s, \[\Delta {{P}_{3}}=(4)\times 3=+12kg-m/s\] So, total change in momentum for 0 to 8 s \[\Delta {{p}_{net}}=\Delta {{p}_{1}}+\Delta {{p}_{2}}+\Delta {{p}_{3}}=(+6-6+12)\] \[=12kg-m/s=12Ns\]
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