A) 25
B) 75
C) 60
D) 50
Correct Answer: B
Solution :
For de-Broglie wavelength \[{{\lambda }_{1}}\frac{h}{p}=\frac{h}{\sqrt{2mK}}\,\] ?.(i) \[{{\lambda }_{2}}=\frac{h}{\sqrt{2m16K}}=\frac{h}{4\sqrt{2mK}}=\frac{{{\lambda }_{1}}}{4}\] ?(ii) \[{{\lambda }_{2}}=25%\,\text{of}\,{{\lambda }_{1}}\] There is 75% change in the wavelength.
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