NEET NEET SOLVED PAPER 2014

  • question_answer
    A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is [AIPMT 2014]

    A)  \[{{p}_{0}}{{V}_{0}}\]

    B)  \[2{{p}_{0}}{{V}_{0}}\]

    C)  \[\frac{{{p}_{0}}{{V}_{0}}}{2}\]

    D)  zero

    Correct Answer: D

    Solution :

    Work done in the cyclic process = Area bound by the closed configuration = Area of closed configuration = \[\left\{ 2\left[ \frac{1}{2}({{v}_{0}}/2)\times {{p}_{0}} \right]+\left\{ -2\left[ \frac{1}{2}({{v}_{0}}/2){{p}_{0}} \right] \right. \right\}\] = zero.


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