A) \[y=\sin (x-2t)\]
B) \[y=\sin (2\pi x-2\pi t)\]
C) \[y=\sin (10\pi x-20\pi t)\]
D) \[y=\sin (2\pi x+2\pi t)\]
Correct Answer: A
Solution :
Given A = 1 m As \[y=a\sin \,(kx-\omega t)\] \[=\sin \left( \frac{2\pi }{2\pi }\times -2\pi \times \frac{1}{\pi }t \right)\] \[=\sin (x-2t)\]
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