A) 0.6
B) 0.06
C) 0.006
D) 6
Correct Answer: B
Solution :
[b] \[1\text{ }eV=1.6\times {{10}^{19}}J\] |
\[1\,J=\frac{1}{1.6\times {{10}^{-19}}}eV\] |
\[{{10}^{-20}}J=\frac{{{10}^{-20}}}{1.6\times {{10}^{-19}}}eV\] |
\[=0.06\,\,eV\] |
You need to login to perform this action.
You will be redirected in
3 sec