NEET Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति NEET PYQ-Work Energy Power and Collision

  • question_answer
    Force F on a particle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12 m is                   [AIPMT (S) 2011]

    A) 21 J

    B) 26 J

    C) 13 J     

    D) 18 J

    Correct Answer: C

    Solution :

    Work done = Area under \[(F-x)\] graph
                \[=2\times (7-3)+\frac{1}{2}\,\times 2\times (12-7)\]
    \[=8+\frac{1}{2}\times 10\]
                \[=8+5=13\,J\]


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