A) 200 J
B) 100 J
C) zero
D) 1000 J
Correct Answer: B
Solution :
| Net work done in sliding a body up to a height h on inclined plane |
| = Work done against gravitational force |
| + Work done against frictional force |
| \[\Rightarrow \] \[W={{W}_{g}}+{{W}_{f}}\] ...(1) |
| but \[W=300\text{ }J\] |
| \[{{W}_{g}}=mgh=2\times 10\times 10=200\text{ }J\] |
| putting in Eq. (i), we get |
| \[300=200+{{W}_{f}}\] |
| \[\Rightarrow \] \[{{W}_{f}}=3000-200=100\,J\] |
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