A) 1.78
B) 1.25
C) 1.59
D) 1.69
Correct Answer: A
Solution :
| [a] \[{{X}_{1}}={{X}_{5th\,dark}}=(2\times 5-1)\frac{\lambda D}{2d}\] |
| \[{{X}_{2}}={{X}_{8th\,dark}}=8\frac{\lambda D}{\mu d}\] |
| \[{{X}_{1}}={{X}_{2}}\] |
| \[\frac{9}{2}\frac{\lambda /D/}{d/}=8\frac{\,\lambda /D/}{\mu d/}\] |
| \[\mu =\frac{16}{9}=1.78\] |
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