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NEET Physics Transmission of Heat NEET PYQ-Transmission Of Heat

  • question_answer
    A slab of stone of area of \[0.36\,{{m}^{2}}\] and thickness 0.1 m is exposed on the lower surface to steam at\[100{}^\circ C\]. A block of ice at \[0{}^\circ C\] rests on the upper surface of the slab. In one hour 4.8 kg of ice is melted. The thermal conductivity of slab is      (Given latent heat of fusion of ice \[=3.36\times {{10}^{5}}J\,k{{g}^{-1}}\])           [AIPMT (M) 2012]

    A)  \[1.24J/m/s/{}^\circ C\]

    B)       \[1.29\text{ }J/m/s/{}^\circ C\]

    C)   \[2.05\text{ }J/m/s/{}^\circ C\]

    D)  \[1.02\text{ }J/m/s/{}^\circ C\]

    Correct Answer: A

    Solution :

    \[\frac{\delta Q}{\delta t}=\frac{KA}{L}({{T}_{1}}-{{T}_{2}})\]
    \[Q=\frac{KA}{L}({{T}_{1}}-{{T}_{2}})\]
    \[Q=m{{L}_{f}}\]
    \[\frac{KA}{L}({{T}_{1}}-{{T}_{2}})t=m{{L}_{f}}\]
    \[K=\frac{m{{L}_{f}}L}{A({{T}_{1}}-{{T}_{2}})t}\]
    \[K=\frac{4.8\times 3.36\times {{10}^{5}}\times 0.1}{0.36\times 100\times 3600}\]
    \[=\frac{4.8\times 3.36}{0.36\times 36}\]
    \[=1.24J/m/{{s}^{o}}C\]


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