NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी NEET PYQ-Thermodynamics

  • question_answer
    The correct option for free expansion of an ideal gas under adiabatic condition is                     [NEET 2020]

    A)  \[q=0,\text{ }\Delta T<0\] and \[w>0\]

    B)  \[q<0,\text{ }\Delta T=0\] and \[w=0\]

    C)  \[q>0,\text{ }\Delta T>0\] and \[w>0\]

    D)  \[q=0,\text{ }\Delta T=0\] and \[w=0\]

    Correct Answer: D

    Solution :

    [d] Free expansion \[\Rightarrow \text{ }{{P}_{ex}}=0\]
                \[\therefore w=-{{P}_{ex}}\Delta V=0\]
                \[\because \]       Adiabatic process \[\Rightarrow q=0\]
    also, \[\Delta U=q+w\] [ first law of thermodynamics]
    \[\therefore \Delta U=0\]
    \[\because \] Internal energy of an ideal gas is a function of temperature
    \[\therefore \] If internal energy remains constant
    \[\therefore \Delta T=0\]


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